all_nested_indices#
- ivy.all_nested_indices(nest=None, /, include_nests=False, _index=None, _base=True)[source]#
Return indices of all the elements in nest.
- Parameters:
nest (
Optional
[Union
[List
,Tuple
,Dict
,Array
,NativeArray
,Container
]], default:None
) – The nest to check the leaves of.include_nests (
bool
, default:False
) – Whether to also include indices of the nests themselves, not only leaves. Default isFalse
._index (
Optional
[Union
[int
,Sequence
[int
]]], default:None
) – The indices detected so far. None at the beginning. Used internally, do not set manually._base (
bool
, default:True
) – Whether the current function call is the first function call in the recursive stack. Used internally, do not set manually.
- Return type:
List
- Returns:
ret – A set of indices of all elements in nest
Examples
With
List
input:>>> x = [189, [863, 672], [264, 384]] >>> y = ivy.all_nested_indices(x) >>> print(y) [[0], [1, 0], [1, 1], [2, 0], [2, 1]]
With
Tuple
input:>>> x = (189, (863, 672), (264, 384)) >>> y = ivy.all_nested_indices(x, include_nests=True) >>> print(y) [[0], [1, 0], [1, 1], [1], [2, 0], [2, 1], [2]]
With
Dict
input:>>> x = {'a': 2., 'b': [6., [15., 9.]], 'c': (7., 56.)} >>> y = ivy.all_nested_indices(x) >>> print(y) [['a'], ['b', 0], ['b', 1, 0], ['b', 1, 1], ['c', 0], ['c', 1]]
With
ivy.Array
input:>>> x = ivy.array([[True, False], [False, False]]) >>> y = ivy.all_nested_indices(x) >>> print(y) [[]]
With
ivy.Container
input:>>> x = ivy.Container(a=ivy.array([412, 948, 482]), b=ivy.array([168, 674, 341])) >>> y = ivy.all_nested_indices(x) >>> print(y) [['a'], ['b']]